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Algebra/Quick Algebra Question(12.7-2)

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Question
Solve the system please:
y = x^2 + 5x + 4
y = 8x + 8
Thank you for your time!

Answer
y = x^2 + 5x + 4
and
y = 8x + 8


so

x^2 + 5x + 4 = 8x + 8


x^2 - 3x - 4 = 0

(x-4)(x+1) = 0

x = 4 or x = -1


if x = 4  , substitute 4 for x in y = 8x + 8


y = 40


if x = -1 , substitute -1 for x in y = 8x + 8

y = 0



so the solutions to the system are


x=4 and y=40  , x=-1 and y=0  

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