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Hi Scott,

I am having trouble with an algebra problem and would appreciate some help and explanation. Here's the problem:

Solve for x; [(a-c*x)/(b+d*x)]+a=0

Thanks,

Sam

Since the term with an a has no x in it, subtract it from both sides.

This gives [(a - cx)/(b + dx)] = -a.

To eliminate fractions, multiply both sides by b + dx.

This gives a - cx = -a(b + dx) => a - cx = -ab -adx.

Move the x terms to the left and the constants (terms without x) to the right.

That means add adx - a to both sides. The result is

adx - cx = -ab - a.

On the left, factor out the x, and on the right, factor out the negative sign.

This gives (ad-c)x = -(ab+a).

The last thing that needs to be done is to divide both sides by (ad-c).

This gives x = -(ab+a)/(ad-c)

.

Algebra

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