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Hi Scott,

I am having trouble with an algebra problem and would appreciate  some help and explanation. Here's the problem:

Solve for x; [(a-c*x)/(b+d*x)]+a=0


Since the term with an a has no x in it, subtract it from both sides.
This gives [(a - cx)/(b + dx)] = -a.

To eliminate fractions, multiply both sides by b + dx.
This gives a - cx = -a(b + dx) => a - cx = -ab -adx.

Move the x terms to the left and the constants (terms without x) to the right.
That means add adx - a to both sides.  The result is
adx - cx = -ab - a.

On the left, factor out the x, and on the right, factor out the negative sign.
This gives (ad-c)x = -(ab+a).

The last thing that needs to be done is to divide both sides by (ad-c).
This gives x = -(ab+a)/(ad-c)


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Scott A Wilson


Any algebraic question you've got. That includes question that are linear, quadratic, exponential, etc.


I have solved story problems, linear equations, parabolic equations. I have also solved some 3rd order equations and equations with multiple variables.

Documents at Boeing in assistance on the manufacturiing floor.

MS at math OSU in mathematics at OSU, 1986. BS at OSU in mathematical sciences (math, statistics, computer science), 1984.

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Both my BS and MS degrees were given with honors.

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Students in a wide variety of areas since the 80's; over 1,000 of them have been in algebra.

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