You are here:

# Algebra/Algebra

Question

-
Question's in the image.

I will rt(5) to mean the root(5), which is the squareroot(5).

As I read the question, the 1st term in brackets on the left becomes 5*rt(5).
The next term turns into 8*rt(5)/5.
The last term turns into -8/5.

The multiplier is 2/(rt(5)+2).

On the right, we have (2/5)(m+nrt(5)).
The equation is then This gives (5*rt(5) + 8*rt(5)/5 - 8/5)(2/(rt(5)+2)) = (2/5)(m+n*rt(5)).

Multiplying by (rt(5)+2))/2 gives 5*rt(5) + 8*rt(5)/5 - 8/5 = ((rt(5)+2)/5)(m+n*rt(5)).

Multiplying by 5 gives 25*rt(5) + 8*rt(5) - 8 = (rt(5)+2)(m+n*rt(5)).

Combining the 1st two terms on the left gives 33*rt(5) - 8 = (rt(5)+2)(m+n*rt(5)).

Multiplying both sides by rt(5)-2 gives 165 - 8*rt(5) - 66*rt(5) + 16 = m+n*rt(5).

Combining terms on the left gives 181 - 75*rt(5).

From here, is can be seen that m = 181 and n = -66.

Algebra

Volunteer

#### Scott A Wilson

##### Expertise

Any algebraic question you've got. That includes question that are linear, quadratic, exponential, etc.

##### Experience

I have solved story problems, linear equations, parabolic equations. I have also solved some 3rd order equations and equations with multiple variables.

Publications
Documents at Boeing in assistance on the manufacturiing floor.

Education/Credentials
MS at math OSU in mathematics at OSU, 1986. BS at OSU in mathematical sciences (math, statistics, computer science), 1984.

Awards and Honors
Both my BS and MS degrees were given with honors.

Past/Present Clients
Students in a wide variety of areas since the 80's; over 1,000 of them have been in algebra.