A man is 24 years older than his son. 12 years ago, he was five times as old as his son. What are the present ages of both?

A man is 24.
Call the father's current age x and the son's current age y.

He is 24 years older, so x = y + 24.

The part on 12 years ago says that x - 12 = 5(y - 12).

Putting in the equation for x gives y + 24 - 12 = 5(y-12).
Simplifying the left and multiplying out the right gives y + 12 = 5y - 60.
Adding -5y - 12 to both sides gives -4y = -72.
Dividing by -4 gives y = 18.

Since x = y + 24, and y = 18, this means x = 42.

Checking out the age 12 years ago means the father was 42-12 = 30
and the son was 18-12=6.  Note that 30 = 5*6, so that's the correct answer.  


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Scott A Wilson


Any algebraic question you've got. That includes question that are linear, quadratic, exponential, etc.


I have solved story problems, linear equations, parabolic equations. I have also solved some 3rd order equations and equations with multiple variables.

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