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Hello Sir,

solve for x and y, if x^2+y^3=5274 and y^2+x^3=7148. I tried many times but i failed. Hope you help.

Thank You.

Since the answers are so large, the answer is probably closer to the number that is cubed.

What I mean is y^3 is close to 5274 and x^3 is close to 7148.

This gives values for x and y as 19.2631888 and 17.40657698.

Since these values are a little bit large, try truncating both answers.

This gives x and y as 19 and 17.

Since it is can be seen that 19*19=361, and 19*361=6859 and the 17*17=289, and 17*289=4913,

this means x^2=361, x^3=6859, y^2=289, and y^3=4913.

Putting these back in the two equations gives 289+6859=7148 and 4913+361=5274.

Looking back at the problem, that's the numbers we're looking for, so that is the answer.

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