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Hi Scott

My non-math mind wants to know the following:

I am reading a textbook where the equation

MOE = PL^3 / 48ID

is presented. Then they solve for D

D = PL^3 / 48(MOE)I.

It looks like they simply had D and MOE change places. But I'm not satisfied. I would like to know the algebra rule whereby the equation can be solved for D.

Thanks!

Pete

Technically, the equation should really be written with parenthesis to be sure the terms are all in the denominator on the right side. Then it would be MOE = PL^3 / (48ID).

If both sides are multiplied by D, that gives MOED on the left side and

on the right side we have DPL^3 / (48ID), and D/D is 1, giving PL^3 / (48I).

Now that we have MOED = PL^3 / (48I), multiply both sides by 1/(MOE).

On the left side, we get MOED / (MOE) = D.

On the right side, we have [PL^3 / (48I)][1/(MOE)].

That multiplies out to PL^3 / (48IMOE).

This makes the final equation be D = PL^3 / (48IMOE).

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Comment | Hey that's a pretty neat trick, Scotto; I'll have to remember that one. Who knows when I'll encounter a similar situation. P |

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