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Hi Scott

My non-math mind wants to know the following:

I am reading a textbook where the equation

MOE = PL^3 / 48ID

is presented.  Then they solve for D

D = PL^3 / 48(MOE)I.

It looks like they simply had D and MOE change places.  But I'm not satisfied.  I would like to know the algebra rule whereby the equation can be solved for D.



Technically, the equation should really be written with parenthesis to be sure the terms are all in the denominator on the right side.  Then it would be MOE = PL^3 / (48ID).

If both sides are multiplied by D, that gives MOED on the left side and
on the right side we have DPL^3 / (48ID), and D/D is 1, giving PL^3 / (48I).

Now that we have MOED = PL^3 / (48I), multiply both sides by 1/(MOE).
On the left side, we get MOED / (MOE) = D.
On the right side, we have [PL^3 / (48I)][1/(MOE)].
That multiplies out to PL^3 / (48IMOE).

This makes the final equation be D = PL^3 / (48IMOE).  


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Scott A Wilson


Any algebraic question you've got. That includes question that are linear, quadratic, exponential, etc.


I have solved story problems, linear equations, parabolic equations. I have also solved some 3rd order equations and equations with multiple variables.

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MS at math OSU in mathematics at OSU, 1986. BS at OSU in mathematical sciences (math, statistics, computer science), 1984.

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