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# Algebra/college algebra

Question
An airplane flew in a direct line from its base at the rate of 300miles an hour and returned over the same route at the rate of 250miles an hour, requiring 15min longer of the returned trip . How far from its base did it fly

Since d = rt.

We know that d = 300t and d = 250(t+15).

Setting these equal gives 300t = 250(t+15).

Multiplying this out gives 300t  = 250t + 3750.

Subtract off 250t from both sides and get 50t = 3750.

Divide both sides by 50 and get t = 75 (yes, that's 3 days and 3 hours).

Put that back in the equation d = 300t and get d = 300*75 = 22,500.
That is, d = 22,500 miles.

Checking this gives 22,500 = 300 * 75, and that is true.
It also gives 22,500 = 250(75+15) = 250*90, and that is also true.

Occasionally math problems don't apply to reality.  See, as a side note, since there are only roughly 25,000 miles around the earth, it might have been quicker to fly 1,500 miles in the opposite direction.  At 300 mph this would have only taken 5 hours and at 250 mph this would have taken 6 hours ...

Algebra

Volunteer

#### Scott A Wilson

##### Expertise

Any algebraic question you've got. That includes question that are linear, quadratic, exponential, etc.

##### Experience

I have solved story problems, linear equations, parabolic equations. I have also solved some 3rd order equations and equations with multiple variables.

Publications
Documents at Boeing in assistance on the manufacturiing floor.

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MS at math OSU in mathematics at OSU, 1986. BS at OSU in mathematical sciences (math, statistics, computer science), 1984.

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Both my BS and MS degrees were given with honors.

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Students in a wide variety of areas since the 80's; over 1,000 of them have been in algebra.