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# Algebra/Algebra

Question

Algebra
yeah sorry that was my bad. The index is x^(5/4).
(Simplify equation)

[(y^ 1/2)/(x^ 3/4) - (x^ 5/4)/(y^ 3/2)]^4

= {(y-x^2)/ [(x^ 3/4)(y^ 3/2)] }^4       (Combine both terms to achieve a common denominator)

= (y-x^2)^4 * 1/[(x^ 3/4)(y^ 3/2)] }^4

= (y-x^2)^4 * 1/[(x^ 3)(y^ 6)] }^4

At this point, you can obtain the binomial series expansion of (y-x^2)^4 , and combine with the product of 1/[(x^ 3)(y^ 6)] }^4  to attain your answer.

Hope it helps. Peace.

Algebra

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