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# Algebra/Finding a graphic solution to an equation

Question
Hi Scott

I've come across a problem whose on-site solution does not appear to be correct.

The topic is "finding the solution to the equation graphically".

The equation is 6(d+2)=4(d-3).
The site shows that the solution is 12.
I believe that 12 is the wrong answer. The correction answer is -12.

Please let me know the correct solution to this problem.

Thanks

Chris

I'm not sure what the correct answer is by looking at the problem.
We need to multiply it out, put the elements with d on one side and
put the constants on the other.

Since 6*2 = 12 and 4*(-3) = -12, multiplying it out gives 6d + 12 = 4d - 12.
To put the d's on the left and the constants on the right, add -4d - 12 to both sides.
This gives 2d = -24.

The last step is to divide both sides by 2.
That gives d = -12.

Yes, it appears that you are correct.  Nowadays, you can probably get on the computer and send this answer to the books publisher to let them know that they have a minor typo in the book.

As I was growing up and studying in school, I noticed errors like that now and then.
It may seem like a lot, but to make every character in a book correct can be difficult.

Questioner's Rating
 Rating(1-10) Knowledgeability = 10 Clarity of Response = 10 Politeness = 10 Comment Thanks, Scott, your reply is much appreciated! Chris

Algebra

Volunteer

#### Scott A Wilson

##### Expertise

Any algebraic question you've got. That includes question that are linear, quadratic, exponential, etc.

##### Experience

I have solved story problems, linear equations, parabolic equations. I have also solved some 3rd order equations and equations with multiple variables.

Publications
Documents at Boeing in assistance on the manufacturiing floor.

Education/Credentials
MS at math OSU in mathematics at OSU, 1986. BS at OSU in mathematical sciences (math, statistics, computer science), 1984.

Awards and Honors
Both my BS and MS degrees were given with honors.

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Students in a wide variety of areas since the 80's; over 1,000 of them have been in algebra.