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# Algebra/albebra

Question
three months ago the tennis pro shop ordered 150 tennis racquets and 50 pairs of tennis shoes for \$14,000 and last week they ordered 80 racquets and 30 tennis shoe at the cost of \$ \$7,650.
What is the cost of a tennis racquets and a pair of tennis shoes to the proprietor??

Let x=the cost per tennis racquet, and y=the cost per pair of tennis shoes.

Thus, we get:
1. 150x + 50 y = \$14,000
and
2. 80x + 30y = \$7,650

We can simplify each... 1. divide through by 50, 2. divide through by 10, to get:
1. 3x + y = \$280
and
2. 8x + 3y = \$765

Solve these for x & y to get x=\$75 and y=\$55.

Hence, a tennis racquet costs \$75 and the shoes cost \$55.

Questioner's Rating
 Rating(1-10) Knowledgeability = 10 Clarity of Response = 10 Politeness = 10 Comment thank very much for your needed help

Algebra

Volunteer

#### Abe Mantell

##### Expertise

Hello, I am a college professor of mathematics and regularly teach all levels from elementary mathematics through differential equations, and would be happy to assist anyone with such questions!

##### Experience

Over 15 years teaching at the college level.

Organizations
NCTM, NYSMATYC, AMATYC, MAA, NYSUT, AFT.

Education/Credentials
B.S. in Mathematics from Rensselaer Polytechnic Institute
M.S. (and A.B.D.) in Applied Mathematics from SUNY @ Stony Brook