Expert: Richard J. Raridon - 8/21/2007

Question
A) Find the equation of the straight line that passes through the point (2,4) and is parallel to the line
2x + 3y -8 = 0

B) Find the equation of the line that is perpendicular to the line 2x + 3y - 8 = 0 at the point (1,2)

please help!

Answer
A) re-write the equation y = (-2/3)x +8/3 so the slope of the line is -2/3.  for the new line, 4 = (-2/3)(2)+b so
b = 16/3 and the equation is y = (-2/3)x +16/3 or
2x +3y = 16
B) the slope of the perpendicular line is 3/2 so you have
2 = (3/2)(1) +b and b = 1/2
the new equation is y = (3/2)x +1/2 or 2y = 3x+1