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Algebra/Application problems

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Question
1.A $5000 investment at an annual simple interest rate of 5.2% earned as much interest after one year as another investment in an account that earned 6.5% annual simple interet. How much was invested at 6.5%?

Answer
Hi Blanca,

First let's find out how much interest was earned on the $5000.

Money invested x rate = interest
$5000*0.052 = $260

So, for the problem, we know the rate(6.5%) and the interest earned ($260), and we want to find the amount invested

Money invested x rate = interest
divide both sides by the rate
Money invested = interest earned / rate
Money invested = 260 / 0.065
Money invested = $4000

This is what we would expect.  It requires less money to get the same interest when you invest it at a higher rate of return.

Let me know if you have any questions.

Bobby

Algebra

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Bobby Soltani

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I can help with all types of questions in algebra, geometry, trigonometry, and calculus. I can answer general physics questions. I can also help simplify and solve word problems.

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I have been a math and physics tutor in college for 3 years.

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Bachelor's and Master's degrees in Electrical Engineering.

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