Algebra/Ball falling + bouncing
Expert: Bobby Soltani - 1/3/2005
QuestionWhat website?
Thank you, this helped a lot. I just want to clarify -
48 * (1 + 13/15) = x
D = x / (1- 13/15)
right?
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Followup To
Question -
When a bouncy ball is dropped from 48" and rebounds 13/15 of its vertical distance each time, what is the distance (in feet) traveled in rebounds?
Answer -
Hi,
Please see the following website for an explanation. It involves an infinite summation that reduces to:
D = h(1+r)/(1-r)
where
D = total distance
h = height dropped (48'')
r = 13/15
I hope this helps. Let me know if you have other questions.
Bobby
AnswerSorry, I forgot to paste the link. Here is the website.
http://www.oakton.edu/acad/dept/mpcs/mat/m251/calculator/calc4/bouncing.htm
Your equation is not quite correct. It should look like this:
D = 48*(1+13/15)/(1-13/15)
13/15 is approximately 0.8667
D = 48*(1+0.8667)/(1-0.8667)
D = 48*(1.8667)/(0.1333)
D = 89.60/0.1333
D = 672.18 inches