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Question
How do you put (2x+1)^2 in standard form
standard form is a(x-h)^2 + k
(2x+1)^2 = 4x^2 + 4x + 1
= 4(x^2 + x + 1/4)
at this point, we usually complete the square in the expression in the parenthesis. But this expression is already a square
= 4 (x+1/2)^2
= 4 (x-(-1/2))^2 + 0
a = 4 , h = -1/2 , k = 0
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