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could you please soleve this for me:
1/3x + 17y=43
10x+3/7y=32
i don't know where to start.
I gather the equations are:
(1/3)x + 17y=43
10x+(3/7)y=32 ....Yes?
If so, then we can solve either by substitution or elimination.
...let's first get rid of the fractions...multiply the first eq. by 3, and the 2nd by 7, to get:
x+51y=129 and
70x+3y=224
From the first one, we get x=129-51y, now substitute
this into the 2nd equation:
70(129-51y)+3y=224
Now solve for Y...then fo x...
Can you finish it from here?
Abe
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Algebra
Answers by Expert:
Abe Mantell
Expertise
Hello, I am a college professor of mathematics and regularly teach all levels from elementary mathematics through differential equations, and would be happy to assist anyone with such questions!
Experience
Over 15 years teaching at the college level.
Organizations
NCTM, NYSMATYC, AMATYC, MAA, NYSUT, AFT.
Education/Credentials
B.S. in Mathematics from Rensselaer Polytechnic Institute
M.S. (and A.B.D.) in Applied Mathematics from SUNY @ Stony Brook
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