You are here:

# Algebra/Algebra Finding X on both sides?

Shai Weezy wrote at 2008-01-14 21:29:40
33+x=x+3

-x -x

----------

33=x+3

-3   -3

----------

30=x

----------

Then

30=x

-  -

3  3

Equal 10 because 3 /3 equal 1 so that don't count. Then 30/3 equals 10 so that will mean X=10

wizzkidd13yrold wrote at 2009-01-08 02:21:36
you start with 33 + 2X = 5X + 3. then, you need to take away one X preferably the smaller one.

33 + 2X = 5X + 3

-2x  -2x

=33=3x+3. the next thing to do is to take away added#.-3  -3

=30=3x. than you divide the 30 by 3x, and your answer is x=10

ahmed wrote at 2010-05-25 17:32:10
what you do is you arange all the numbers by them selves and the x's by themselves, when you do that the operation you were using before become's the opposite for e.g if you were adding it become's minus.

then you calculate it, and divide the number s remaining.

so his is how it goes

33+2x=5x+3

33-3=5x-2x

30-3x

30 divide by 3

which equals 10

so x's equals ten

PaulaAnne wrote at 2010-12-02 09:12:22
hi, this is what my math teacher taught us;

33+2x=5x+3

transpose all variables to the left side and all non variable to the right, changing their signs when transposed.

2x-5x=3-33

so 2-5= is -3. 3-33= -30

so the problem would be

-3x=-30

since your x still has a number, divide both sides by that number. note that if the sign is negative, divide both sides by negative and same with positive. i should look like this

-3x/-3=-30/-3

cancel out both negative threes to leave only a positive X. -30 divided by -3 is 10. note that dividing two numbers with the same sign will result in a positive answer.

x=10

Checking;

33+(2)(10)=(5)(10)+3

33+20=50+3

53=53

hope that helps.

bob wrote at 2013-01-04 01:45:25
You have this equation:

33 + 2X = 5X + 3

What’s 5 -2? Meaning 5x minus 2x

You’ll get 0

Then you get:

33=3X+3

33 minus 3 equals 30. 30 divided by 3 equals 10.

So X= 10.

X=10

Algebra

Volunteer

#### Cindy Myers

##### Expertise

I can assist with basic and intermediate algebra. I can greatly simplify the process for solving equations with one variable and solving linear systems with 2 variables. I can explain how to graph linear equations. I can`t answer questions about graphing non-linear equations (circles, parabolas, hyperbolas, etc.).

##### Experience

I have tutored basic algebra for over 30 years. I have also taught classes to prepare students for the PSAT, SAT, GRE and GMAT -- all of which feature algebra questions in a variety of formats.

Education/Credentials
BA