Expert: Richard J. Raridon - 7/13/2004

Question
36x^3-84x^2+49x
36m^2-64
5x^3+45
5(x-8)(3x-10)=0
2n^2-50=0
9n^2=12n-4
24x^2+26x=5
1/3w^2=4/5w
(2x-3)(x+4)=4x+43
Find two consecutive even integers whose product is 224.

Answer
36x^3-84x^2+49x = x(6x-7)^2
36m^2-64 = (6m-8)(6m+8)
5x^3+45 = 5(x+3)(x^2-3x+1)
5(x-8)(3x-10) = 15x^2-170x+400
2n^2-50 = 2(n+5)(n-5)
9n^2-12n+4 = (3n-2)^2
24x^2+26x-5 = (6x-1)(4x+5)
you should write it (1/3)w^2 = (4/5)w
then w(w/3-4/5) = 0 and w = 0, 12/5
2x^2+5x-12 = 4x+43 so 2x^2+x-55 = (2x+11)(x-5)
let the integers be x and x+2
so x(x+2) = 224
x^2+2x-224 = (x+16)(x-14) and the integers are 14 and 16
or -16 and -14