Expert: Richard J. Raridon - 2/8/2006

Question
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Followup To
Question -
Hi Thanks again for your help!Here are a few questions for you.
1)write the equation in logarithmic form for:
a)3^2=9
b)27^2/3=9
2)Write the equation log81 243=5/4 in exponential form. (not sure how to write that the 81 is below log)
3)Write in exponential form:d=log79^c.
(would that be 79=c^d?)
4)Evaluate: log8 1/64
(i'm confused its either 2,-2,3 or -3)
thanks aagin!
Answer -
1a) log base 3 of 9 = 2
b) log base 27 of 9 = 2/3
2) 81^5/4 = 243
3)
4) -2 since 8^-2 = 1/64

Thanks for your help!
On #3 was my answer right?
Here are a couple follow ups.
1)Express in terms of logarithms of x,y,and z: log basea 5xy^4/z^2
2) write as a longarithm of a single expression:log base b 8x+3(log base b x-log base b y)
Thanks again. You are very smart!

Answer
Your answer to #3 was not right.  You can check it by putting c=2, calculating d and seeing that c^d does not = 79.  You don't usually have exponents inside a log function.
I'll pass on your two new ones.  I don't know what to do with logs within logs.  They didn't teach that when I was in school 60 years ago.