Expert: Bobby Soltani - 12/13/2005

Question
six r square - r - 2=0
solve for r should have two solutions

Answer
Hi Diana,

You can solve this problem using the quadratic formula.

root #1 = (-b + SQRT(b^2 - 4ac))/(2a)
root #2 = (-b - SQRT(b^2 - 4ac))/(2a)

where the equation is in the form ax^2 + bx + c = 0

For our equation, we have a = 6, b = -1, and c = -2

root #1 = (1 + SQRT(1 + 48))/12 = 8/12 = 2/3

root #2 = (1 - SQRT(1 + 48))/12 = -6/12 = -0.5

Let me know if you have any questions.

Bobby