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Algebra/thank you for the help im slowly learning.

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Question
1.x-6/x+2 divided by x+8/x+5
2.7/6x^2r+10/3xr^2
3.2a+6/a^2+6a+9 + 1/a+3
4.8/2a-2b - 3b/a^2-b^2
5.what are the excluded values of y in the expression: y^2+y-2/y^2-2y-15 times y^2-5y+5/y^2+5y+6
6.use long division to find the quotient(t^2+4t-6)divided by (t+5)
7.solve by making a list. how many whole numbers between 1 and 100 either contain the digit 7 or are divisible by 7 but do not satisfy both of these conditions?
8.a-3/10 + a-5/5 = 1.5
9.(2/x+2)=9 over 8 -(5x/4x+8)
10.solve y over c + n over d=5 for n

Answer
You need to use parentheses to make things clearer
1. (x-6)/(x+2) * (x+5)/(x+8) = (x-6)(x+5)/[(x+2)(x+8)]
2. 7/(6x^2r) +10/(3xr^2) = (7r+10x)/(6x^2r^2)
3. 2(a+3)/(a+3)^2  +1/(a+3) = 3/(a+3)
4. 8/[2(a-b)] -3b/[(a+b)(a-b)] = (4a+b)/(a^2-b^2)
5. Are you sure you wrote this right, since y^2-5y+5 will not factor?
6. t-1 with a remainder of -1
7. you can do this.  the first one is 14
8. (a-3)/10 +(a-5)/5 = 1.5 multiply by 10 to get
a-3 +2a -10 = 15 so a = 28/3
9 and 10. what are the = signs for?

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