Algebra/vertex

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Expert: - 7/21/2005


Question
find the vertex of this parabola: x= 3y^2 + 19


thanks Bobby

Answer
Hi Jeremy,

To find the vertex of a parabola, you need to get the equation into the form below.  Then, (x0,y0) is the vertex and c is a constant.

(y-y0)^2 = c(x-x0)

x= 3y^2 + 19
subtract 19
(x-19) = 3(y - 0)^2
divide by 3
(y - 0)^2 = (1/3)(x - 19)
so, x0 = 19, and y0 = 0.

The vertex is (19,0)

Let me know if you have any questions.

Bobby

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Bobby Soltani

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I can help with all types of questions in algebra, geometry, trigonometry, and calculus. I can answer general physics questions. I can also help simplify and solve word problems.

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I have been a math and physics tutor in college for 3 years.

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