Basic Math/Algebra Review
Expert: Lynn Houston - 8/11/2008
QuestionWe have homework that is a review before the school year starts and I do not remember how to solve the following:
Solve the following. The domain is the set of complex numbers.
2(M-2)>4-3(1-M)
lwl + 4(greater then or equal to)6
Any help you could give would be appreciated.
Thanks
Gwen
Answer2(M-2)>4-3(1-M) Do the multiplication
2M-4> 4-3+3m combine like terms
2m-4> 1+3m add 4 to both sides
2m > 5 + 3m subtract 3m from both sides
-m > 5 divide both sides by -1 and remember that you have to change the sign when dividing by a negative
m < -5
lwl + 4(greater then or equal to)6
I'm not sure what the first part of this one is, can you clarify. Is it the absolute value of w? I think it is, so I'll answer for that.
lwl + 4>= 6 subtract - 4 from both sides
| w | >= 2 so w >= 2 or w <= -2
If you have any questions, let me know.