Question of the three numbers,second is twice the first and is also thrice the third.if the average of the three numbers is 44, the largest number is:"
plz explain with complete steps
Answer the numbers are a, b and c
these facts are given in the problem
a+b+c/3 = 44 (a+b+c = 132)
a = b/2
c = b/3
b/2 + b + b/3 = 132 (multiply everything by 6 to get rid of the fractions)
3b + 6b + 2b = 792
11b = 792
b = 72, therefore, a = 36 and c = 24
