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Basic Math/Problem solving

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Question
If a computer teacher has 20 students, 8 of whom are women and 12 of whom are men. If her afternoon class has 30 students, how many of them must be women so that both classes have the same ratio of women to men?

Answer
let x = women and y = men

8/12 = x/y

x+y = 30
x = 30-y substitute the value of x into the first eq

8/12 = (30-y)/y  multiply both sides by 12y

8y = 12(30-y)  multiply
8y = 360 - 12y  add 12y to both sides
20y = 360  divide both sides by 20
y = 18, therefore x = 12  so 12 must be woman

Basic Math

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Lynn Houston

Expertise

I can answer questions in basic algebra and any grade school math.

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Love math, currently helping my nephew get through Intermediate Algebra.

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I majored in Math Ed in college (but decided not to teach), so have over 40 credits of math.

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