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Question
Show all calculations for the following questions:

     1. Slope-Intercept form:   y = -2x - 6   

     Identify three points on the graph where this equation would run through using the substitution method of x or y. Show all work at arriving at each point. You will receive 25 points for your correct answers and 25 points for showing all work at arriving at your results.



2. What is the equation of a line running through the following points?: (6,4) and (-6,8)

What is the slope of this equation? What is the y-intercept of this equation?

Name an equation parallel to this equation?    perpendicular?

In each of the following two problems are the following lines AB and CD parallel, perpendicular or neither?

a) A(1,1), B(-1,2) and C(1,-1), D(0,-3)

b) A(0,4), B(-2,-2) and C(1,-1) and D(0,-4)

If an equation passed through the following points (1,6) and (9,10), the slope would be 1/2.

Identity two points where if an equation passed through you would get:

a) a slope of -3/4

b) a slope of 3

b) a slope of 0

Convert the following two equations to slope-intercept form:


a) 1/3x + 3 = 3/4y

b) 3x -4y - 20 = 0  

Answer
Hello Rebecca
For this problem you just have to substitute any value of X and find the value of Y as long as the domain of the equation is all real numbers.
Let’s take 0, 3 and 5
Y(0) = 0-6
Y = -6
{0, -6}
Y(3) = -6 – 6
Y = -12
{3, -12}
Y(5) = -10 – 6
Y = -16
{5, -16}
2. What is the equation of a line running through the following points?: (6,4) and (-6,8)

First compute the slope of the line
It is -1/3
Y = (-1/3)X + b
To find b just substitute one of the coordinates.
4 = (-1/3)*6 + b
4 = -2 + b
B = 6
So the equation of the line is
Y = (-1/3)X + 6
By the way the slope intercept of the equation is 6 where X = 0
Name an equation parallel to this equation?    perpendicular?

To find a line which is parallel to this equation, observe that parallel lines have equal slopes.
So Y = (-1/3)X + b
They only differ in their y intercepts.
So take any coordinate and substitute it in the equation to find b
I chose {1, 2}
2 =  (-1/3)*1 + b
B = 7/3
So the equation of the line is;
Y = (-1/3)X + 7/3
To find a line which is perpendicular, observe that perpendicular lines have slopes whose product is -1
Therefore the slope of any perpendicular line the above line has a slope 3 RIGHT check the product.
Y = 3X + b
Take any coordinate you like, {0, 1}
1 = 0 + b
B = 1
Y = 3X + 1
I’ve almost solved all of it you should try the remaining and if you get stumped don’t hesitate to ask questions.
Thankz
Michael

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Michael Tadesse

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I can answer questions regarding Relations, linear functions and equations, Squares and square roots, Translation and Similarity, Special Properties of Right Angled Triangles, Measurement of Area and Volume, algebra. I can also answer questions related to Pre calculus, Limits and Continuity, Derivatives Applications of Derivatives, High school math in general. I can’t answer questions of the following type. Power Series, Multiple Integrals, Fourier series, Vector valued Functions.

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I love mathematics as it is the mother of all sciences. I had an outstanding math results while I was in school. The tradition continues while I am in university. I have been helping elementary school Students for the past five years with mathematics problems. In fact, I have a brother who is four years younger than me I usually help him to understand what the crux of the question is before trying to solve it. He loves math very much, he is indeed one of the top scorers form his class in Mathematics. I didn’t stop helping my younger relatives after I joined the Engineering campus and I am more than ready to help anyone with my skill.

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I have a high school diploma with a 3.97 GPA; I also have many merit certificates granted for my outstanding results in high school math. I won a merit certificate for my participation in the Black Month Essay Contest. I took two different National Examinations in 2006 and 2007. In the former Exam I got 9As which includes Mathematics. I also have a score of 90 out of hundred in the later Examination which is the toughest known in Ethiopia. So you don’t have to worry about my ability to help my clients.

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I have never had an online client but I was helping students coming to me for assistance in Mathematics.

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