You are here:

- Home
- Science
- Math for Kids
- Basic Math
- Advanced Algebra

Advertisement

Hello -- I'm having some difficulty understanding and simplifying (algebraically) the following:

g(x)= 3f(x+1)-2

Can you explain this to me/ thanks .. Angelo

Angelo,

f(x), g(x) etc are functions of the variables given in the brackets.

Let us take a simpler example: f(x) = x + 2

So f(2) = 2+2 =4.

Now you have been given g(x)= 3f(x+1)-2. This means that g(x) is a function of f(x+1). For this to solve, we need to know f(x) which is not given in your example. Let us assume f(x) = x+2.

Considering this,

f(x+1 = (x+1)+2 . Note that we have replaces x with x+2 here as this is a function of x+1 and not x.

Thus, f(x+1) = x+3

We will substitute this in g(x)

Thus,

g(x) = 3[x+3]-2 = 3x+9-2 = 3x+7

So if you are asked to find g(4), then it will equal to 3(4)+7 = 19

You can find g(x) for any x provided you know the equation for f(x).

I hope that this is clear. Please let me know if you need additional information.

All the best.

Regards,

Pawan

- Add to this Answer
- Ask a Question

Rating(1-10) | Knowledgeability = 10 | Clarity of Response = 8 | Politeness = 10 |

Comment | No Comment |

I can answer Basic Mathematics questions like: Natural Numbers, Integers, Real Numbers, Complex Numbers, Number Theory, Geometry, Trigonometry, Graph Theory, Square Roots, Basic Integration, Profit-Loss problems, Work-Time problems, Equations etc I can try to answer questions of probability and set theory

Tutoring on allexperts.com since long time**Education/Credentials**

I am Bachelor of Engineering (Instrumentation) from the reputed institute in India.**Awards and Honors**

I was 18th in High School Scholarship examination in Maharashtra State of India.
I was second in Mathematics in Maharashtra State in Secondary School Certificate examination.