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I have this word problem in this ASVAB test study book that I hope u can help me with.

"A Lion runs 50 mph in pursuit of a Zebra running at 40 mph. If the initial distance between them was a quarter of a mile, how long will it take the Lion to catch the Zebra?"

By the way, this is a multiple choice problem & they are:

A) 1.5 mins

B) 1 min

C) 2 mins

D) 1 .5 hours

Can u please tell me how u got the answer as well. Thank you"

The Lion gains 10 miles every hour he's chasing the Zebra, so it's as simple as dividing 1/4 mile by 10. It will take 1/40th of an hour (60/40) to catch the Zebra or 1.5 minutes. If you want the algebraic explanation... d=tr (distance = time x rate (or speed)). You want to know when both the zebra and lion get to the same point, so let's let the distance the zebra runs = y, so the distance the lion has to run to catch it when starting a quarter mile behind is y + .25. Fill in the info you know to the distance formula, using 2 separate equations. Lion: y + .25 = 50t. Zebra: y=40t. Using the value of y = 40t, to solve the other equation gives you

40t + .25 = 50t

.25 = 10t

.25/10 = t

.025 = t

Since the time is in miles per hour, 60(.025) = 1.5 minutes.

I can answer questions in basic algebra and any grade school math.

Love math, currently helping my nephew get through Intermediate Algebra.**Education/Credentials**

I majored in Math Ed in college (but decided not to teach), so have over 40 credits of math.