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When I work through problems, I emphasize principles and key ideas which I believe are worth noting. I will try to answer questions in the following areas, but not at the advanced level. Algebra. Sequences & Series. Trigonometry. Functions & Graphs. Coordinate Geometry. Quadratic Polynomials. Exponentials & Logarithms. Basic Calculus. Probability, Permutations and Combinations. Mathematical Induction. Complex numbers. Physics problems.

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I have worked as a teaching assistant in college. My hope is that more people will share knowledge without boundary, give help without seeking recognition or monetary rewards.

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See a selection of past questions in my maths repository under "Question Archive"

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Bachelor degree in Engineering Science.
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You are here:  Experts > Science > Math for Kids > Basic Math > Fractional Parts Equaling One

Basic Math - Fractional Parts Equaling One


Expert: Josh - 12/7/2005

Question
Hello:

How can the unknown amounts be determined for the following calculation?

(What fractional part of 1) X 0.05) + (What fractional part of 1) X 0.02) = 0.04?

Note that the fractions must equal 1.

Answers: 2/3 and 1/3,  2/3 + 1/3 = 1

Check: (2/3 X 0.05) + (1/3 X 0.02) = 0.10/3 +  0.02/3 = 0.12/3 = 0.04

If possible, use a simple calculation for determining the missing fractional amounts

I thank you for your reply.

Answer
Hello,

I don't think it matters whether we are dealing with fractions or not. We can let "x" and "y" be the two unknown quantities. They have to satisfy the constraint that they add up to one.

So, we have x+y=1. Rearranging this, we get y=1-x.
So, the original problem:
"Find x and y, such that 0.05*x + 0.02*y = 0.04"
may be rewritten as
"Find x, such that 0.05*x + 0.02*(1-x) = 0.04".

Expanding the LHS:
0.05*x+0.02-0.02x=0.04
0.03*x=0.02
=> x=2/3, y=1-x.

Regards.  

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