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Basic Math/Solving a equation

Expert: Josh - 2/17/2004

Question

1-[(1-t)^(a-1)/a]=G, a>1,0<t<1,0<G<1.

Find "a" from the above equation.

Answer
Do you mean 1-[(1-t)^((a-1)/a)]=G ?
1-[(1-t)^((a-1)/a)]=G
1-G=[(1-t)^((a-1)/a)]
log(1-G)=log[(1-t)^((a-1)/a)]
log(1-G)=((a-1)/a).log(1-t)
a.log(1-G)=(a-1).log(1-t)
log(1-t)=a.log(1-t)-a.log(1-G)
log(1-t)=a[log(1-t)-log(1-G)]
a=log(1-t)/[[log(1-t)-log(1-G)]]

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Josh

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When I work through problems, I like to emphasize concepts which I believe are worth noting. I will try to answer questions in the following areas, but not at the advanced level. Algebra. Sequences & Series. Trigonometry. Functions & Graphs. Coordinate Geometry. Quadratic Polynomials. Exponential & Logarithms. Basic Calculus. Probability, Permutation and Combination. Mathematical Induction. Complex numbers. Physics problems.

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I have worked as a teaching assistant in college. My hope is that more people will share knowledge without boundary, give help without seeking recognition or monetary rewards.

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Bachelor degree in Engineering Science

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