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Biology/Antisceptic alcohol concentrations

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Question
I work in a food safety lab and prepare many packaged products for analysis by spraying with an ethanol/methanol solution prior to sampling.  It is my understanding that a 70% dilution of ethanol (or other alcohol) is the most effective/lethal concentration to effectively kill vegetative state microorganisms.  The stock solution I use for preparing the diluted stock is 85% ethanol, denatured with 15% methanol.  To achieve peak bactericidal concentrations and maximum economic use of the stock should I be diluting the ethanol to a 70% dilution or the stock in its entirety to a 70% dilution.

I appreciate your consideration on the matter and look forward to your response.

Answer
You ask a good question, Richard, one that highlights the importance of attention to detail. Because the stock solution is only 85% ethanol, diluting the entire stock solution to 70% will result in an ethanol concentration below 70%, and thus below the preferred bactericidal concentration. Hence, you should be diluting the ethanol itself to a 70% concentration; the methanol that's present will also have a bactericidal effect, but you can't treat it as thought it's necessarily cumulative. That is, you can't assume that the bacteria surviving treatment with ethanol will necessarily be killed by methanol exposure. If ethanol is your bactericidal agent, then that's the substance you must dilute to 70% concentration.

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