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Why Array index in C Language begins at 0[zero]?
This has something to do with the way pointers work.
Array name is a constant pointer pointing to the base address of the memory at which array starts. When you use array[i], the compiler calculates it as *(array + i). Since array is the address of the first element, the value of i will be 0 for accessing it. That's why array index starts at 0.
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Narendra
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