Expert: Narendra - 7/2/2006

Question

hello narendra

i m unable to understand this code.pls explain
how these parametrs are passing .
void pascal f(int i,int j,int k)

     {

     printf(“%d %d %d”,i, j, k);

     }

     void cdecl f(int i,int j,int k)

     {

     printf(“%d %d %d”,i, j, k);

     }

     main()

     {

     int i=10;

     f(i++,i++,i++);

     printf(" %d\n",i);

     i=10;

     f(i++,i++,i++);

     printf(" %d",i);

}
i was expecting
10 10 10 13
10 10 10 13

but Answer  is


     10 11 12 13

     12 11 10 13

make it clear
thank you
monika  

Answer
I don't understand what you are doing!
Why 2 functions with the same kind of body!?

You are passing i++ to a function.
So, the arguments will be processed from right to left.
And the function will be passed 12, 11 and 10.
And the same will be printed.

I don't see any confusion here.
Also, the two calls to the same function cannot print two different answers!