Expert: Joydeep Bhattacharya - 3/5/2007

Question
Hi, How can I open a file input.txt
with the form

__________
n
word
word
word


abcdefgijl
ijklmnñov
wordxvvc
___________

n is a number, that tells me the number of words that follows here rows
n = 3; i only know the number untill i read it;

How can i save the 3 types of data here into differents arrays because i will use them later

1.- n = the number of words = n
2.- word = is an array =arrayword
3.- abcdef... = other array =arraypuzzle




I have this so far
CODE


#include<stdio.h>
#include <stdlib.h>
#include<conio.h>
#include<string.h>
#define MAXLEN 15

FILE *Entrada;
FILE *Salida;
void main()
{
int i,n;
char s;
char arreglopalabra[];
char puzzle[];

Entrada=fopen("C:\\TC\\BIN\\input.txt", "r");
Salida=fopen("C:\\TC\\BIN\\output.txt", "w");

if (Entrada==NULL || Salida==NULL)
{
 printf("ERROR");
 getch();
 return;
}
else
{
    while(!feof(Entrada))
    {
       fscanf(Entrada," %d %s ", &n, &arreglopalabra, &puzzle);

       fprintf(Salida, " %d %s ", n, arreglopalabra, puzzle);

    }


}

clrscr();
printf("\n %d %s", n, palabra);
getch();
fclose(Entrada);
fclose(Salida);
}


Answer
Hi Edgar

 When you are trying to create the array dynamically after reading the file's first line where you have the data stored for you then its a better approach to read the number from the file and then create the array dynamically [creating array on runtime]

keep a pointer like :

   int*p;
   p=(int *)malloc(sizeof(int)*n);

Now use this dynamically created array to store the datas from the file and use it to your convinience.

In case of any doubts or clarification regarding anything please feel free to get back to me.

regards
Joydeep Bhattacharya