Calculus/Maximum-minimum problem.
Expert: Paul Klarreich - 10/29/2008
QuestionTwo sides of fencing are needed to enclose a rectangular area at the corner of a room. If 20 ft of fencing is provided, find the area of he largest possible rectangle.
AnswerQuestioner: Samantha
Category: Calculus
Private: No
Subject: word problems (technology)
Question: Two sides of fencing are needed to enclose a rectangular area at the corner of a room. If 20 ft of fencing is provided, find the area of he largest possible rectangle.
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Hi, Sam,
If this is your first time doing a Maximum-minimum problem, here is the scheme.
1. Identify the variables in the problem -- the things that change. Give them names.
2. Find the one that is to be 'optimized'. Write it as a function of the other variables.
3. If it is a function of more than one, use the other conditions (constraints) to eliminate all but one.
4. Differentiate, set that = 0, solve for your 'stationary' point.
5. Consider whether it is a maximum, minimum, or neither. Check the logical endpoints, too.
6. Answer whatever other questions are asked.
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Variables:
x = first side of the rectangle
y = second side
A = area of rectangle
Relation:
A = xy
Constraint: x + y = 20
Solve: y = 20 - x
A = x(20 - x)
A = 20x - x^2
You can finish it up from here.