Calculus/Maximum-minimum problems
Expert: Paul Klarreich - 10/14/2008
QuestionYes sorry the 7.5cm,15cm,7.5 are 7.5cm____/7.5cm
15cm
For a gutter with the sides of 7.5cm bent at an angle, calculate theta
to find the maximum volume of flow through the gutter.
Thanks
AnswerQuestioner: Larissa
Category: Calculus
Private: No
Subject: The gutter problem
Question: Yes sorry the 7.5cm,15cm,7.5 are 7.5cm____/7.5cm
15cm
For a gutter with the sides of 7.5cm bent at an angle, calculate theta
to find the maximum volume of flow through the gutter.
Thanks
...................................
Hi Larissa,
Is this your first attempt at Max-min problems? If so, the scheme is something like this:
Oh, wait -- I said that already. But it applies.
You want to maximize the cross-section are a, meaning the area of the trapezoid. So here
is what you will do:
1. You will draw a diagram.
2. You will determine the height and OTHER base of the trapezoid, based on the angle theta
that you see in this picture (it's just labeled 't')
15 + 2x
--------------+
\ / |
\ 7.5/ | h
\ /t |
-------....+
15 x
Use your trig.
h = 7.5 sin t
x = 7.5 cos t
A = h/2(b1 + b2) << area formula for a trapezoid
A = 7.5 sin t(15 + 15 + 2(7.5 cos t))/2
A = 7.5 sin t(30 + 15 cos t)/2
A = (7.5*15/2) sin t(2 + cos t)
Now ignore the constant and take:
A* = sin t(2 + cos t)
to be maxed:
A' = sin t(-sin t) + cos t(2 + cos t)
A' = - sin^2 t + 2 cos t + cos^2 t
make all cosines: Remember: sin^2 = 1 - cos^2
A' = cos^2 - 1 + 2 cos t + cos^2 t
A' = 2 cos^2 t + 2 cos t - 1
Solve for cos t using the quadratic formula:
-2 +- sqrt(4 + 4)
cos t = -----------------
4
-2 +- 2 sqrt(2)
cos t = -----------------
4
-1 +- sqrt(2)
cos t = -----------------
2
You want the positive root, because t must be in [0,pi/2]
So: just compute
-1 + sqrt(2)
cos t = -------------
2
and plug that into your calculator. You can do the rest.