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Calculus/Velocity and Rate of Change (Calculus)

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Question
The position (x-coordinate) of a particle moving on the line y = 2 is given by x(t) = 2t^3 -13t^2 + 22t - 5 where t is time in seconds.
a. Describe the motion of the particle for t>= 0.
b. When does the particle speed up? slow down?
c. When does the particle change direction?
d. When is the particle at rest?
e. Describe the velocity and speed of the particle?
f. When is the particle at the point (5, 2)?

Answer
The particle is moving in a straight line, with increase & decrease
in it's velocity.
When x'(t)=0 then the particle is at rest.
When X(t)=0 then the particle is changing direction.
The particle speed_up/slow_down when the derivative x'(t)>0/x'(t)<0
f. When is the particle at the point (5, 2)?, It's the same as asking
when x=5 ? it happens when t=0.75 & t=4.13

Alon.

Calculus

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Alon Mandes

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Kind of questions I can answer : Limits, Derivatives, Integration, Implicit functions, continuousity, differentiation ,Extremum problems, Lagrange multipliers, Gradients, Surface integrals, Multi variables functions ,Multi variables Integrals,Complex variables ,Complex functions, Curves, Trajectory integrals & Vector analyse,Divergence,Rotor & word problems. Kind of question I can't answer : Economics,Combinatorics,infinite series & convergence ,Statistics & Probabilities .

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1. I'm a team member of mathnerds (math site for answering questions) 2. I'm a team member in the Student's Union of the Technion, helping students who have problems in mathematics. 3. 2 years of experience as a math teacher in college. 4. I give free homework help for high school students in Mathematics & Physics. 5. I teach part time in collage the subjects : "Digital Signal Processing" , "Random Signals & Noise" , "Complex Functions".

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Hi-Tech company : GSM4VOIP ; job possition : Algorythm developer.

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M.A in Mathematics & Bs.c in Electronics.

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