Calculus/calculus 2

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Question
Water in a bowl evaporates at a rate proportional to the area of the surface of the water. In other words, the rate of decrease of the volume is proportional to the area of the surface. Show that the depth of water decreases at a constant rate regardless of the shape of the bowl.

Answer
The amount of water decrease at a rate the is proportionate to the surface area.  The volume of water that decrases can be seen to be
A dv where is the surface area and dV is the change in volume.

If you take to jars with surface areas A2 and A2, changes in volume V1 and V2, the rate of change in the first jar is A1 dV1 and the rate of change in second har is A2 dV2.

dV1 = k / A1 and dV2 = k / A2.

Putting these back into are equations show that both jars decrease in surface level at k.  

Calculus

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Any kind of calculus question you want. I also have answered some questions in Physics (mass, momentum, falling bodies), Chemistry (charge, reactions, symbols, molecules), and Biology.

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Experience in the area: I have tutored students in all areas of mathematics for over 25 years. Education/Credentials: BSand MS in Mathematics from Oregon State University, where I completed sophomore course in Physics and Chemistry. I received both degrees with high honors. Awards and Honors: I have passed Actuarial tests 100, 110, and 135.

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