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Question
Find the derivative of y= sin^2 (4x) cos (3x) with respect to x
Here are the rules that we will use to solve the problem :
1. (fg)'=f'g+fg'
2. sin^2(ax)'=2a*cos(ax)
3. cos(bx)'=-b*sin(bx)
Ok, let's get to work :
y=sin^2(4x)*cos(3x)
y'=[sin^2(4x)]'*cos(3x)+sin^2(4x)*[cos(3x)]'
y'=8*cos(4x)*cos(3x)-sin^2(4x)*3*sin(3x)
Alon.
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Answers by Expert:
Alon Mandes
Expertise
Kind of questions I can answer : Limits, Derivatives, Integration, Implicit functions, continuousity, differentiation ,Extremum problems, Lagrange multipliers, Gradients, Surface integrals, Multi variables functions ,Multi variables Integrals,Complex variables ,Complex functions, Curves, Trajectory integrals & Vector analyse,Divergence,Rotor & word problems. Kind of question I can't answer : Economics,Combinatorics,infinite series & convergence ,Statistics & Probabilities .
Experience
1. I'm a team member of mathnerds (math site for answering questions)
2. I'm a team member in the Student's Union of the Technion, helping
students who have problems in mathematics.
3. 2 years of experience as a math teacher in college.
4. I give free homework help for high school students in
Mathematics & Physics.
5. I teach part time in collage the subjects : "Digital Signal Processing" , "Random Signals & Noise" ,
"Complex Functions".
Organizations
Hi-Tech company : GSM4VOIP ; job possition : Algorythm developer.
Education/Credentials
M.A in Mathematics & Bs.c in Electronics.
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