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Expert: Alon Mandes - 11/3/2008


Question
What is the f"(x) of f(x)=(2x-5)/(x^2-4)

Answer
f(x)=(2x-5)/(x^2-4) To derive the function we will follow the
rule : [f/g]'=[f'g-g'f]/g^2
f'(x)=[(2x-5)'(x^2-4)-(2x-5)(x^2-4)']/(x^2-4)^2
=[2(x^2-4)-2x(2x-5)]/(x^2-4)^2
=[2x^2-8-4x^2+10x]/(x^2-4)^2
=[-2x^2+10x-8]/(x^2-4)^2
f''(x)={ [-4x+10][x^2-4]^2-[-2x^2+10x-8]2[x^2-4] } / { (x^2-4)^2 }.
I'll leave from here for you to proceed the calculation.

Alon.

Calculus

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Alon Mandes

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Kind of questions I can answer : Limits, Derivatives, Integration, Implicit functions, continuousity, differentiation ,Extremum problems, Lagrange multipliers, Gradients, Surface integrals, Multi variables functions ,Multi variables Integrals,Complex variables ,Complex functions, Curves, Trajectory integrals & Vector analyse,Divergence,Rotor & word problems. Kind of question I can't answer : Economics,Combinatorics,infinite series & convergence ,Statistics & Probabilities .

Experience

1. I'm a team member of mathnerds (math site for answering questions) 2. I'm a team member in the Student's Union of the Technion, helping students who have problems in mathematics. 3. 2 years of experience as a math teacher in college. 4. I give free homework help for high school students in Mathematics & Physics. 5. I teach part time in collage the subjects : "Digital Signal Processing" , "Random Signals & Noise" , "Complex Functions".

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Hi-Tech company : GSM4VOIP ; job possition : Algorythm developer.

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M.A in Mathematics & Bs.c in Electronics.

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