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Calculus/Absolute max and min, inflection points, and determine whether or not they're in the interval

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Expert: Alon Mandes - 11/20/2008


Question
y= 3x^2-12x+5

Answer
1st of all this quadratic equation has 1 critical point , that can
be max or min depends on the 2nd derivative.
y'=6x-12. y'=0 -> 6x-12=0 -> x=2.
y''=6 > 0 it's a minimum. This is local min.
Let's calculate absolute min : Since this function is concave
upward, from the critical point and on the function rises all the
time, so our absolute min is the local minimum.

Alon.

Calculus

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Alon Mandes

Expertise

Kind of questions I can answer : Limits, Derivatives, Integration, Implicit functions, continuousity, differentiation ,Extremum problems, Lagrange multipliers, Gradients, Surface integrals, Multi variables functions ,Multi variables Integrals,Complex variables ,Complex functions, Curves, Trajectory integrals & Vector analyse,Divergence,Rotor & word problems. Kind of question I can't answer : Economics,Combinatorics,infinite series & convergence ,Statistics & Probabilities .

Experience

1. I'm a team member of mathnerds (math site for answering questions) 2. I'm a team member in the Student's Union of the Technion, helping students who have problems in mathematics. 3. 2 years of experience as a math teacher in college. 4. I give free homework help for high school students in Mathematics & Physics. 5. I teach part time in collage the subjects : "Digital Signal Processing" , "Random Signals & Noise" , "Complex Functions".

Organizations
Hi-Tech company : GSM4VOIP ; job possition : Algorythm developer.

Education/Credentials
M.A in Mathematics & Bs.c in Electronics.

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