Calculus/Calculus 1

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Question
an object is thrown upwards from the ground w/an initial velocity of 128 ft/sec use: s(t)=-16t^2+vo(t)+so to model this situation.
a)what are the position,velocity & acceleration equations?
b)how high will the object go?
c)what will the velocity(in mph) be at the moment that the object returns to the ground ?

Answer
Let's use the position or height function : S(t)=so+vot+(1/2)at^2.
In our case so=0 because the object is thrown from the grown, &
a<0 because the direction is upwards, & the only acceleration exists
is the grivitation. Thus :
a) S(t)=128t-16t^2 , v(t)=S'(t)=128-32t , a(t)=v'(t)=-32.
b) Let's derive to find the maximum : S'(t)=128-32t , S'(t)=0 ->
128=32t -> t=4 -> S(4)=128*4-16*16=256 ft.
c)The velocity of the impact is the same as the initial velocity
128 ft/sec. You need to converted to mph.

Alon.

Calculus

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Alon Mandes

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Kind of questions I can answer : Limits, Derivatives, Integration, Implicit functions, continuousity, differentiation ,Extremum problems, Lagrange multipliers, Gradients, Surface integrals, Multi variables functions ,Multi variables Integrals,Complex variables ,Complex functions, Curves, Trajectory integrals & Vector analyse,Divergence,Rotor & word problems. Kind of question I can't answer : Economics,Combinatorics,infinite series & convergence ,Statistics & Probabilities .

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