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Question
I can't see how to use calc for the following problem, I can do it with Geometry though, please help.
Consider a room in the shape of a cube, 4 meters on each side. A bug at point P wants to walk to point Q at the opposite corner, Use calculus to determine the shortest path

Answer
Consider unfolding the room.  The bugs is in the upper corner of one square and where he is walking to is in the lower corner of the adjacent square.

The shortest line is a straight line from one corner to the other.
The length of it would be √(8²+4²) = 4√3.

To do this problem with calculus, consider some point x units from the ground on the corner between them.  The total distance travelled would be √[4²+(4-x)²] + √(x²+4²).  The function can be reduced to
√[32-8x+x²] + √(x²+16).

To find the minimum, take the derivative and set to 0.
(x-4)/√(32-8x+x²) + x/√(x²+4²) = 0.

As you can see, geometrically, the problem is much easier to find.

Note that the path could be in any of 3 directions.  The bug needs to choose one of the adjacent walls or the ceiling.  Once this choice has been made, he can walk in any direction to the point halfway along the opposing edge, then walk to the other corner.

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Just to put in some comedy, note that bugs aren't that bright.  They can't even comprehend where they are going and certainly don't care how long it takes to get there.  Maybe that makes you smile.

Calculus

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