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Calculus/sum of infinite series

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Question
i need to find the sum of the series (2+(-1/3)^n)/2^n from n=0 to inf. i really have no idea how to do these kind of problems any help is greatly appreciated. thanks
drae

Answer

∑ { [2+(-1/3)^2]/2^n } =
n=0


∑ { 2/2^n+(-1)^n/6^n } =
n=0

 ∞                ∞
2 ∑ { (1/2)^n } + ∑ { (-1)^n/6^n } =
 n=0             n=0

=2/(1-1/2) + 1 - 1/6 + 1/36 -1/216 + 1/1296 - 1/7776 + 1/46656 - 1/279936 +..

=4 + 1 - 1/6 + 1/36 -1/216 + 1/1296 - 1/7776 + 1/46656 - 1/279936 +..

=4 + 1/(1-36) - (1/216)*[1+1/36+1/1296+....

=4 + 36/35 - (1/216)*[1/1-36]

=4 + (36/35) - (1/216)*(36/35)

=4 + (36/35)(1-1/216)

=4 + (36/35)(215/216)

5.02.

Alon.

Calculus

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Kind of questions I can answer : Limits, Derivatives, Integration, Implicit functions, continuousity, differentiation ,Extremum problems, Lagrange multipliers, Gradients, Surface integrals, Multi variables functions ,Multi variables Integrals,Complex variables ,Complex functions, Curves, Trajectory integrals & Vector analyse,Divergence,Rotor & word problems. Kind of question I can't answer : Economics,Combinatorics,infinite series & convergence ,Statistics & Probabilities .

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