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Question
when determining higher order derivatives, do you always expect to eventually get "(d^n)y/dx^n=0
Usually (d^n)y/dx^n means the nth derivative. (d^1)y/dx^1, usually written as dy/dx is the first derivative, (d^2)y/dx^2 is the second derivative, etc. They can be set equal to zero and solved. The first derivative tells the maxima conditions and the second one gives the inflection points.
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Scotto
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Any kind of calculus question you want. I also have answered some questions in Physics (mass, momentum, falling bodies), Chemistry (charge, reactions, symbols, molecules), and Biology.
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I graduated with honors in both my BS and MS degree from Oregon State University.
I was allowed to jump into a few junior level courses my sophomore year.
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