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Question
If you can help me answer this problem that wouls be greatly appreciated.
A company wishes to manufacture a box with a volume os 52 cubic feet that is open on the top and is twice as long as it is wide. Find the width of the box that can be produced the minmum amount of material. Round to the nearest tenth, if necessary.
Take h=height, w=width, and l=length, then we have v=volume=52=hwl.
We know that l=2w, so volume we 2hw^2. We know this value is 52, so h can be solved for in this equation.
Since the box has two sides and a bottom, outside area is
2hl + 2hw + lw.
The variables h and l are in terms of w (once you have solved the equations given), so put these into the equation to get it in terms of w.
Once this has been done, set the equation = 0 and solve for w. This would be the minimum.
Hope this answers it for you but please write back for any additional help.
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Scotto
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Any kind of calculus question you want. I also have answered some questions in Physics (mass, momentum, falling bodies), Chemistry (charge, reactions, symbols, molecules), and Biology.
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