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Expert: - 4/14/2008


Question
I wish to use 300 meters of fencing to enclose a rectangular plot. Part of the fencing will be used to divide this area into two identical, adjacent plots. What dimensions will make the combined area of the plots as large as possible.

Answer
Problem: Maximize area A=WL; use 3W+2L=300.

I get that you should divide the fence in half.
Divide half into two sides (each 75 feet).
Divide other half into 3 pieces (each 50 feet).

This gives you an area of 3,750 meters^2.

For an actual field, we're done.

For a math class, the results need to be expanded to say how we got there by substitution and taking derivatives.

Calculus

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Any kind of calculus question you want. I also have answered some questions in Physics (mass, momentum, falling bodies), Chemistry (charge, reactions, symbols, molecules), and Biology.

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Experience in the area: I have tutored students in all areas of mathematics for over 25 years. Education/Credentials: BSand MS in Mathematics from Oregon State University, where I completed sophomore course in Physics and Chemistry. I received both degrees with high honors. Awards and Honors: I have passed Actuarial tests 100, 110, and 135.

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Maybe not a publication, but I have respond to well oveer 7,500 questions on the PC. Well over 2,000 of them have been in calculus.

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I aquired well over 40 hours of upper division courses. This was well over the number that were required. I graduated with honors in both my BS and MS degree from Oregon State University. I was allowed to jump into a few junior level courses my sophomore year.

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My past clients have been students at OSU, students at the college in South Seattle, referals from a company, friends and aquantenances, people from my church, and people like you from all over the world.

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