Calculus/Curve sketching with derivatives.
Expert: Paul Klarreich - 5/27/2008
QuestionLet f(x) be the function defined by f(x)=sin^(2)x-sinx for 0 <(less than or equal to) x <(less than or equal to) 3pie (3.14). Determine the exact values of the x-intercepts of the graph of f(x). Use calculus to determine the intervals on which f(x) is increasing. Find the x-values for which the tangent to f(x) is parallel to the horizontal axis.
Answer
Questioner: harman
Category: Calculus
Private: No
Subject: ap calculus
Question: Let f(x) be the function defined by f(x)=sin^(2)x-sinx for 0 <(less than or equal to) x <(less than or equal to) 3pie (3.14). Determine the exact values of the x-intercepts of the graph of f(x). Use calculus to determine the intervals on which f(x) is increasing. Find the x-values for which the tangent to f(x) is parallel to the horizontal axis.
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Hi, Harman,
Since you didn't indicate what, if anything, you already did on these, I will assume you just don't know how to get started.
f(x) = sin^2(x) - sinx for 0 <= x <= 3pi [really 3pi?]
Determine the exact values of the x-intercepts of the graph of f(x).
Solve the equation sin^2(x) - sinx = 0
Factor: sin x(sin x - 1) = 0
Solve: sin x = 0 and sin x = 1.
Now use your knowledge of the graph of sin x to get your values -> x = 0, pi/2, pi, 2pi.
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Use calculus to determine the intervals on which f(x) is increasing.
Find the x-values for which the tangent to f(x) is parallel to the horizontal axis.
Get f'(x) = 2 sin x cos x - cos x.
Set that = 0:
2 sin x cos x - cos x = 0
Factor (like the other)
cos x(2 sin x - 1) = 0
As before, use your knowledge of the graph of sin x (and cos x) to get your values.
Solve cos x = 0, --> x = pi/2, 3pi/2
sin x = 1/2. --> x = pi/6, 5pi/6
Finally, use those to SEPARATE regions where the graph is rising (increasing) from where the graph is falling.
(see the attached graph)