AboutScotto Expertise Any kind of mathematics (calculus, analysis, game theory, linear approximation, finite differences, linear regression, linear programming, numerical analysis, probability, statistics, etc.).
I also have answered some questions in
Physics (mass, momentum, falling bodies),
Chemistry (charge, reactions, symbols, molecules), and
Biology.
Experience Experience in the area: I have tutored students in all areas of mathematics for over 20 years.
Education/Credentials: BSand MS in Mathematics from Oregon State University, where I completed sophomore course in Physics and Chemistry. I received both degrees with high honors.
Awards and Honors: I have passed Actuarial tests 100, 110, and 135.
Publications Maybe not a publication, but I have respond to well oveer 3000 questions on the PC.
That's around 2,000 in basic math and 1,000 in advanced math.
Education/Credentials I aquired well over 40 hours of upper division courses. This was well over the number that were required.
I graduated with honors in both my BS and MS degree from Oregon State University.
I was allowed to jump into a few junior level courses my sophomore year.
Awards and Honors I have been nominated as the expert of the month several times.
All of my scores right now are at least a 9.8 average (out of 10).
Past/Present Clients My past clients have been students at OSU, students at the college in South Seattle,
referals from a company, friends and aquantenances, people from my church, and people like you.
Question Please help! I'm not sure how to do this one and I must have it done by tomorrow (6-27-08)! I was able to do all of the indefinite integrals but this one is a definite and I am confused. Please give me step by step of how to do this.
Question: Evaluate the definite integral ∫[0,4] ((x)/(sqrt(1+2x)))dx
(Note: The interval [0,4] follows the integral sign directly with the 4 being above the 0)
***I have attempted this problem and gotten (1/2)∫[1,9] ((x)/(sqrt(u)))du by determining that u= 1+2x, du= 2dx, and du/2= sx as well as u=1 when x=0 and u=9 when x=4 (which are my new intervals). Please let me know if I was on the right track!!! I really appreciate it and hope you can help.
Answer Have you ever done ∫u dv = uv - ∫v du?
Let u=x, then du=dx.
Let dv = 1/(sqrt(1+2x)) dx, so v = sqrt((1+2x) since the half and the two cancel in the derivative.
The variables u and v are now both known, so all that has to be done is to integrate v. The variable v is just (1+2x)^0.5. Don't forget to worry about d(2x)/dx=2 when doing this.
