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Calculus/Exponentials

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Question
Mathematical proof of f(0) = 1 where f(x)= a^x.

Answer
x^n means take 1 and multiply it by x for a total of n times.

Since x, the number times it is multiplied is 0, the answer starts as 1 and stops as 1.

Consider all numbers raised to the 0.  The function is then a^x where x is zero and a can vary.  Take the derivative and you get xa^(x-1).  Since x is 0, this makes the entire derivative 0.  This means the function has no slope and is a constant for all a.

If you take a number, say 2, and let the power approach zero, you get close to 2.  That looks like and epsilon-delta proof, if you've heard of those.  Take any epslion close to 1, and you can get a delta so that if the power is smaller than delta, then how far from the number you are is less than epsilon.

This can also be tried on any calculator.  Take any number a and put it to the 0 power.  You get 1.

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