Calculus/vectors..

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Expert: - 6/15/2008


Question
i don't know how to draw the diagram, I'm having a great deal of trouble interpreting the question. can you please go into detail about what the question is really asking and how to draw the diagram. question: a crank is pushed by a 40-N force. The shaft of the Crank is 18 cm long. Find the magnitude of the torque, in newton-meters, about the pivot point.

Answer
I'll assume that the crank is being pushed at the opposite end of where it is anchored.  I'll also assume that the force is perpendicular to the shaft.  To get the torque (newtow-meters), take the following equation: T = rF (Torque = radius * Force).  Note that the 18 cm is really to be taken as 0.018 meters.

A good place to look and see the actual problem written out would be http://en.wikipedia.org/wiki/Torque (this is a safe area as far as PCs go).

Thanks for the great question and I hope this answers it.

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